Solve this Exponential Function?
(3x-4)^2x^2 = (3x-4)^5x-2
please help!
(3x-4)^2x^2 = (3x-4)^5x-2
please help!
?
Favorite Answer
since the bases are the same, the exponents must also be equal, so
2x² = 5x - 2
now solve the resulting quadratic to get
x = 1/2 or x = 2
...also, if the base is 1 or 0 then you will also have solutions, so solve 3x-4=1 and 3x-4=0
Wise man
x=2
Como
Presentation, due to lack of brackets , is meaningless.
Can but GUESS that you mean :-
(3x - 4)^(2 x ²) = (3x - 4)^(5x - 2)
2x ² = 5x - 2
2 x ² - 5x + 2 = 0
( 2x - 1) (x - 2) = 0
x = 1/2 , x = 2
PS
In a subject such as this , should not have to guess ? !
mrkleen340
http://www.wolframalpha.com/input/?i=%283x-4%29^%282x^2%29+%3D+%283x-4%29^%285x-2%29
x = 2
x = 1/2
x = 5/3
x = 4/3