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Dr. Who
Dr. Who asked in Science & MathematicsMathematics · 1 decade ago

Solve this Exponential Function?

(3x-4)^2x^2 = (3x-4)^5x-2

please help!

4 Answers

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  • Steven
    Lv 6
    1 decade ago
    Favorite Answer

    since the bases are the same, the exponents must also be equal, so

    2x² = 5x - 2

    now solve the resulting quadratic to get

    x = 1/2 or x = 2

    ...also, if the base is 1 or 0 then you will also have solutions, so solve 3x-4=1 and 3x-4=0

  • Wise man
    1 decade ago

    x=2

    Source(s): books
  • Como
    Lv 7
    1 decade ago

    Presentation, due to lack of brackets , is meaningless.

    Can but GUESS that you mean :-

    (3x - 4)^(2 x ²) = (3x - 4)^(5x - 2)

    2x ² = 5x - 2

    2 x ² - 5x + 2 = 0

    ( 2x - 1) (x - 2) = 0

    x = 1/2 , x = 2

    PS

    In a subject such as this , should not have to guess ? !

  • mrkleen340
    Lv 5
    1 decade ago

    http://www.wolframalpha.com/input/?i=%283x-4%29^%2...

    x = 2

    x = 1/2

    x = 5/3

    x = 4/3

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