Solve 2sinx - 1 = 0 for 0 <= x < 2(pi)?

Rudy A2011-02-14T20:41:02Z

Favorite Answer

2sinx - 1 = 0
2sinx = 1
sinx =1/2

x = π/6 , 5π/6

pankaj2011-02-15T04:41:09Z

2sinx-1 =0
2sinx= 1
sinx = 1/2
for 0 <= x < 2(pi), x=pi/6, 5pi/6

Ask Me2011-02-15T04:36:20Z

sinx=1/2

sin^-1(1/2) = pi/6