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Solve 2sinx - 1 = 0 for 0 <= x < 2(pi)?

3 Answers

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  • Rudy A
    Lv 6
    1 decade ago
    Favorite Answer

    2sinx - 1 = 0

    2sinx = 1

    sinx =1/2

    x = π/6 , 5π/6

  • 1 decade ago

    2sinx-1 =0

    2sinx= 1

    sinx = 1/2

    for 0 <= x < 2(pi), x=pi/6, 5pi/6

  • 1 decade ago

    sinx=1/2

    sin^-1(1/2) = pi/6

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