How do you solve f (-3 ) + h (2) ?

How do you solve f (-3 ) + h (2) if f(x)=4x-3 and h(x)=-5x+7 ? I just got stumped :(

2011-03-31T20:42:10Z

UPDATE:

So by following the first reply answer I did

f(-3) = 4*(-3)-3, which equals f(-3) = -15

AND

h(2) = -5*2+7 which equals h(2) = 3

Then I added -15 + 3 and got -12, which I presume is my answer.

Is this correct?

2011-03-31T20:44:55Z

Oops, I mean -5*2+7 which equals h(2) = -3

Added -15 + -3 equals -18.

Anonymous2011-03-31T20:33:50Z

Favorite Answer

plug in x= -3 in the f(x) function and x=2 in the h(x) function.

so,

f(-3) + h(2) = 4(-3) - 3 + [ (-5 x 2) + 7 ] = -12 -3 - 10 +7 = -18



UPDATE : You are not right follow my answer or answer 3 below.

UPDATE 2 : Yes you are correct this time.

PatsLax392011-04-01T03:34:03Z

f(-3)= 4(-3) -3 so thats -15
h(2)= -5(2)+7 so thats -3

-15+-3= -18

im prettysure thats how you do it

?2011-04-01T03:32:33Z

plug -3 for the values of x on f(x) and plug 2 for the values of x on h(x), then solve the two equations and add them