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How do you solve f (-3 ) + h (2) ?
How do you solve f (-3 ) + h (2) if f(x)=4x-3 and h(x)=-5x+7 ? I just got stumped :(
UPDATE:
So by following the first reply answer I did
f(-3) = 4*(-3)-3, which equals f(-3) = -15
AND
h(2) = -5*2+7 which equals h(2) = 3
Then I added -15 + 3 and got -12, which I presume is my answer.
Is this correct?
Oops, I mean -5*2+7 which equals h(2) = -3
Added -15 + -3 equals -18.
3 Answers
- Anonymous1 decade agoFavorite Answer
plug in x= -3 in the f(x) function and x=2 in the h(x) function.
so,
f(-3) + h(2) = 4(-3) - 3 + [ (-5 x 2) + 7 ] = -12 -3 - 10 +7 = -18
UPDATE : You are not right follow my answer or answer 3 below.
UPDATE 2 : Yes you are correct this time.
Source(s): B.S in Mathematics - 1 decade ago
f(-3)= 4(-3) -3 so thats -15
h(2)= -5(2)+7 so thats -3
-15+-3= -18
im prettysure thats how you do it
- OrcLv 41 decade ago
plug -3 for the values of x on f(x) and plug 2 for the values of x on h(x), then solve the two equations and add them