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The length of a rectangle is 3m less than 5 times its width. If the perimeter of the rectangle is 102m, what are the dimensions of the rectangle?

3 Answers

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  • 5 days ago

    The length of the rectangle is 3m less than 5 times its width.

    If width of the rectangle = w m, 

    Length = 5 x - 3

    Now Perimeter of a rectangle = 2 [ length + breadth ]

    => 2 [ ( 5 x - 3 ) + x ]  =  102 m................ (given)

    => 5 x - 3 + x  =  102/2  =  51 m

    => 6 x - 3  =  51

    =>  x = 9

    Hence  Length of the rectangle =  5 x - 3  =  5 (9) - 3  =  42 m ........ Answer

    Width = x = 9 m .................... Answer

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  • ?
    Lv 7
    6 days ago

    length of a rectangle is 3m less than 5 times its width

    l = 5w - 3

    the perimeter of the rectangle is 102m

    2l + 2w = 102

    l + w = 51

    Substitute for l

    (5w - 3) + w = 51

    6w - 3 = 51

    Add 3 to both sides

    6w = 54

    Divide both sides by 6

    w = 9 <–––– width

    l = 5w - 3

    l = 5(9) - 3

    l = 42 <––––– length

  • Bryce
    Lv 7
    6 days ago

    l - 3= 5w; l= 5w + 3

    p= 2l + 2w= 10w + 6 + 2w= 12w + 6

    102= 12w + 6

    12w= 96; w= 8 m, l= 43 m

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