Can someone help solve this word problem for me on Mathematics?

Town A has an area of 600km square and a population density of 12 people per km square. Town B has an area of 400km square and a population density of 20 people per Km square. What will be the population density to the nearest whole number of the two towns combined.rest whole number of the two towns combined.

?2011-08-04T01:23:25Z

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Population = Area × Density

Area of Town A = 600 km.²
Area of Town B = 400 km.²
Total area = 600 + 400 = 1,000 km.²

Population density of Town A = 12 people / km.²
Population density of Town B = 20 people / km.²

Population of Town A = 600 × 12 = 7,200 people
Population of Town B = 400 × 20 = 8,000 people
Total population = 7,200 + 8,000 = 15,200 people

Total population density = Total Population / Total area
Total population density = 15,200 / 1,000
Total population density = 15.2 ≈ 15 people / km.²

Hope this helps
Bye !!

?2011-08-04T01:29:11Z

Town A population is 600 x 12 =7200
Town B population is 400 x 20 = 8000
Combined density would be 15200/1000 = 15.2 person per sq km.
Answer : 15 person per sq km

?2011-08-04T00:28:12Z

Town A=600/12=50
Town B=400/20=20

70 people

Anonymous2011-08-04T00:39:17Z

Final combined density is (how many people)/(total area).

Total how many people = 600*12 + 400*20, units are "people".
Total area = 600 + 400, unit is square kilometers.

Population density combined of those two towns = (600*12+400*20)/(600+400)
=(7200+8000)/1000
=15200/1000
=about 15 people per km squared

?2011-08-04T00:44:35Z

population of town a = 600*12 =7200
population of town b = 400*20 = 8000

population density of town a & b = 15200 / 32