what is the 5th term of the sequence a= 2n(n^2-1)?

please show and explain your work

?2012-09-30T18:08:25Z

Favorite Answer

replace n with 5 and do the arithmetic:
a = 2(5)(5²-1) = 2*5*(25-1) = 2*5*24 = 240

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Anonymous2016-12-11T16:37:41Z

This properly universal series of numbers is universal simply by fact the Fibonacci huge style (or Fibonacci series) and could be represented mathematically as Fn= Fn-a million + Fn-2... following this formula, the subsequent 3 numbers on your series is as a result 21, 34 & 55. wish this helps! all the perfect, Peter G

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