what is the 5th term of the sequence a= 2n(n^2-1)?

replace n with 5 and do the arithmetic:

a = 2(5)(5²-1) = 2*5*(25-1) = 2*5*24 = 240

This properly universal series of numbers is universal simply by fact the Fibonacci huge style (or Fibonacci series) and could be represented mathematically as Fn= Fn-a million + Fn-2... following this formula, the subsequent 3 numbers on your series is as a result 21, 34 & 55. wish this helps! all the perfect, Peter G