Algebra 2/Trigonometry help?!?
Solve for x: x^2=4x
Simplify 7 radical 3 / 2 radical 5
if f(x)=x+1 and g(x)= x^2-1 find the value(s) of x for which the expression (g of f) (x) equals 0.
Thank you very much!
Solve for x: x^2=4x
Simplify 7 radical 3 / 2 radical 5
if f(x)=x+1 and g(x)= x^2-1 find the value(s) of x for which the expression (g of f) (x) equals 0.
Thank you very much!
RU Matt
Favorite Answer
x^2 = 4x
Move to the same side:
x^2 - 4x = 0
Factor out an x:
x * (x - 4) = 0
This yields two solutions:
x = 0 and x = 4
----
7sqrt(3)/2sqrt(5)
Rationalize by multiplying by sqrt(5)/sqrt(5) to get:
7sqrt(3)sqrt(5) / 2sqrt(5)sqrt(5)
Combine the roots:
7sqrt(15) / 2(5)
Simplify:
7sqrt(15) / 10
----
f(x) = x + 1 and g(x) = x^2 - 1
To create the composite function, replace all x's in the g-expression with the f(x) expression:
g(f(x)) = (x + 1)^2 - 1
Expand by FOIL:
g(f(x)) = x^2 + 2x + 1 - 1
Simplify:
g(f(x)) = x^2 + 2x
Set this equal to 0:
x^2 + 2x = 0
Factor out x:
x * (x + 2) = 0
Thus, there are two solutions:
x = 0 and x = -2
Anonymous
x^2 = 4x
x^2 - 4x = 0
x(x-4) = 0
x = 0 and x =4
g of f =g( f(x) )
={f(x)}^2 - 1
=(x + 1)^2 - 1
(g of f ) = x^2 + 2x
0 = x^2 + 2x
0 = x(x + 2 )
x = 0 or x = -2
A A
For the first one:
x^2=4x you subtract 4x from both sides
=> x^2-4x=0 and you can then factor out an x and solve (you will get two solutions).
2nd:
I'm not sure how to interpret what you have written.
3rd:
You have f(x) = x+1,
you then plug that into g(x) to get: g(x+1) = (x+1)^2-1 and set it equal to zero.
Brigardo
in the first equation: divide by x. x=4
I don't really know what you meant by the second one, it wasn't really clear
g(f(x)) = (x+1)^2 - 1
(x+1) (x+1) -1 = x^2 +2x +1 -1 = x^2 +2x. Factor to get x(x + 2) = 0. x = 0, and x + 2 = 0
x = -2
x = 0