find the product of z=1+j and √3-j?

Question

please help me guys .with this little problem , im having a trouble solving here in my house...): please help

billrussell42 · Accepted Answer

(1+j)(√3–j)
3 – j + j√3 – j²
3 + j(√3 – 1) + 1
4 + j(√3 – 1)
4 + j(0.732)

edit, correction:
(1+j)(√3–j)
√3 – j + j√3 – j²
√3 + j(√3 – 1) + 1
1 + √3 + j(√3 – 1)
2.732 + j(0.732)

Surya Prakash Reddy Adapa · Answer

(1+i)(sqrt(3)-j)
= sqrt(3) - j + sqrt(3)*j + 1
= [sqrt(3)+1] + j[sqrt(3)-1]
= [1.732+1]   + j[1.732-1]
= 2.732+j0.732

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