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find the product of z=1+j and √3-j?
please help me guys .with this little problem , im having a trouble solving here in my house...): please help
2 Answers
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- billrussell42Lv 78 years agoFavorite Answer
(1+j)(√3–j)
3 – j + j√3 – j²
3 + j(√3 – 1) + 1
4 + j(√3 – 1)
4 + j(0.732)
edit, correction:
(1+j)(√3–j)
√3 – j + j√3 – j²
√3 + j(√3 – 1) + 1
1 + √3 + j(√3 – 1)
2.732 + j(0.732)
- 8 years ago
(1+i)(sqrt(3)-j)
= sqrt(3) - j + sqrt(3)*j + 1
= [sqrt(3)+1] + j[sqrt(3)-1]
= [1.732+1] + j[1.732-1]
= 2.732+j0.732
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