math simplification problem ALGEBRA?
(5/6)z+(4/3)=-(5/3)z-(1/8)
z=????
Everything in parenthesis are fractions
(5/6)z+(4/3)=-(5/3)z-(1/8)
z=????
Everything in parenthesis are fractions
Anonymous
Favorite Answer
(5/6)z+(4/3)=-(5/3)z-(1/8)
Combine like terms:
(5/6)z+(5/3)z= -1/8 - 4/3
5z/6 + 5z/3 = -1/8 - 4/3
5z/6 + (5z*2 / 3*2) = -1/8 - 4/3
5z/6 + 10z/6 = (-3-32)/24
(5z+10z)/6 = -35/24
15z/6 = -35/24
15z * 24 = 6 * -35
360z = -210
z=-210/360
z=-7/12
.....
MDenise
Either multiply the whole thing by 24 to eliminate the fractions, or rewrite the fractions so that they have the same denominator of 24.
Either way, you get, either for the whole thing or for the numerators:
(5*4)z + (4*8) = (-5*8)z - 3
20z + 32 = -40z - 3
20z + 40z = -3 - 32
60z = -35
z = -35/60 = -7/12
ranjankar
5/6z +4/3 = - 5/3z - 1/8
MULTIPLY BOTH SIDES BY 24
20z + 32 = -40z - 3
60z = -35
z = -35/60 = - 7/12 ANSWER
moe
(5/6)z+(4/3)=-(5/3)z-(1/8) or
5/6z+5/3z = -1/8 - 4/3 = -35/24 or
15/6z = -35/24 or
z = -(35/24) * (6/15) = -7/12 <= ANS