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math simplification problem ALGEBRA?

(5/6)z+(4/3)=-(5/3)z-(1/8)

z=????

Everything in parenthesis are fractions

4 Answers

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  • Anonymous
    8 years ago
    Favorite Answer

    (5/6)z+(4/3)=-(5/3)z-(1/8)

    Combine like terms:

    (5/6)z+(5/3)z= -1/8 - 4/3

    5z/6 + 5z/3 = -1/8 - 4/3

    5z/6 + (5z*2 / 3*2) = -1/8 - 4/3

    5z/6 + 10z/6 = (-3-32)/24

    (5z+10z)/6 = -35/24

    15z/6 = -35/24

    15z * 24 = 6 * -35

    360z = -210

    z=-210/360

    z=-7/12

    .....

  • 8 years ago

    Either multiply the whole thing by 24 to eliminate the fractions, or rewrite the fractions so that they have the same denominator of 24.

    Either way, you get, either for the whole thing or for the numerators:

    (5*4)z + (4*8) = (-5*8)z - 3

    20z + 32 = -40z - 3

    20z + 40z = -3 - 32

    60z = -35

    z = -35/60 = -7/12

  • 8 years ago

    5/6z +4/3 = - 5/3z - 1/8

    MULTIPLY BOTH SIDES BY 24

    20z + 32 = -40z - 3

    60z = -35

    z = -35/60 = - 7/12 ANSWER

  • moe
    Lv 7
    8 years ago

    (5/6)z+(4/3)=-(5/3)z-(1/8) or

    5/6z+5/3z = -1/8 - 4/3 = -35/24 or

    15/6z = -35/24 or

    z = -(35/24) * (6/15) = -7/12 <= ANS

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