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math simplification problem ALGEBRA?
(5/6)z+(4/3)=-(5/3)z-(1/8)
z=????
Everything in parenthesis are fractions
4 Answers
- Anonymous8 years agoFavorite Answer
(5/6)z+(4/3)=-(5/3)z-(1/8)
Combine like terms:
(5/6)z+(5/3)z= -1/8 - 4/3
5z/6 + 5z/3 = -1/8 - 4/3
5z/6 + (5z*2 / 3*2) = -1/8 - 4/3
5z/6 + 10z/6 = (-3-32)/24
(5z+10z)/6 = -35/24
15z/6 = -35/24
15z * 24 = 6 * -35
360z = -210
z=-210/360
z=-7/12
.....
- MDeniseLv 58 years ago
Either multiply the whole thing by 24 to eliminate the fractions, or rewrite the fractions so that they have the same denominator of 24.
Either way, you get, either for the whole thing or for the numerators:
(5*4)z + (4*8) = (-5*8)z - 3
20z + 32 = -40z - 3
20z + 40z = -3 - 32
60z = -35
z = -35/60 = -7/12
- ranjankarLv 78 years ago
5/6z +4/3 = - 5/3z - 1/8
MULTIPLY BOTH SIDES BY 24
20z + 32 = -40z - 3
60z = -35
z = -35/60 = - 7/12 ANSWER
- moeLv 78 years ago
(5/6)z+(4/3)=-(5/3)z-(1/8) or
5/6z+5/3z = -1/8 - 4/3 = -35/24 or
15/6z = -35/24 or
z = -(35/24) * (6/15) = -7/12 <= ANS