Compute the discriminant. Then determine the number and type of solutions for the given equation.?

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In ax^2 + bx + c = 0

Discriminant = b^2 - 4ac

In x^2 - 4x + 3 = 0

Discriminant = -4^2 - 4*1*3 = 16 - 4 = 12

Since b^2 - 4ac is greater than 0, there are two real distinct roots (two unequal real solutions)...Show more

B^2-4ac, b=-4, a=1, c=3. Disc =4 . 2 distinct solutions, of course real!...Show more

x²-4x+3=0

d=V(-4)²-4*1*3)
d=V16-12
d=V4
d=+ou-2

x'=(4+2):2
x'=6/2
x'=3

x"=(4-2):2
x"=2/2
x"=1...Show more