Compute the discriminant. Then determine the number and type of solutions for the given equation.?

Question

Compute the discriminant. Then determine the number and type of solutions for the given equation.

x2 - 4x + 3 = 0

       0; one real solution
       -28; no real solution
       4; one real solution
       4; two unequal real solutions

Admire · Accepted Answer

In ax^2 + bx + c = 0

Discriminant = b^2 - 4ac

In x^2 - 4x + 3 = 0

Discriminant = -4^2 - 4*1*3 = 16 - 4 = 12

Since b^2 - 4ac is greater than 0, there are two real distinct roots (two unequal real solutions)

PChaudhary · Answer

B^2-4ac, b=-4, a=1, c=3. Disc =4 . 2 distinct solutions, of course real!

sombra · Answer

x²-4x+3=0

d=V(-4)²-4*1*3)
d=V16-12
d=V4
d=+ou-2

x'=(4+2):2
x'=6/2
x'=3

x"=(4-2):2
x"=2/2
x"=1

Compute the discriminant. Then determine the number and type of solutions for the given equation.?

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