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nameizmel
nameizmel asked in Science & MathematicsMathematics · 8 years ago

Compute the discriminant. Then determine the number and type of solutions for the given equation.?

Compute the discriminant. Then determine the number and type of solutions for the given equation.

x2 - 4x + 3 = 0

0; one real solution

-28; no real solution

4; one real solution

4; two unequal real solutions

3 Answers

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  • Admire
    Lv 7
    8 years ago
    Favorite Answer

    In ax^2 + bx + c = 0

    Discriminant = b^2 - 4ac

    In x^2 - 4x + 3 = 0

    Discriminant = -4^2 - 4*1*3 = 16 - 4 = 12

    Since b^2 - 4ac is greater than 0, there are two real distinct roots (two unequal real solutions)

  • PChaudhary
    8 years ago

    B^2-4ac, b=-4, a=1, c=3. Disc =4 . 2 distinct solutions, of course real!

    Source(s): I was paying attn in my algebra class.
  • sombra
    Lv 7
    8 years ago

    x²-4x+3=0

    d=V(-4)²-4*1*3)

    d=V16-12

    d=V4

    d=+ou-2

    x'=(4+2):2

    x'=6/2

    x'=3

    x"=(4-2):2

    x"=2/2

    x"=1

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