A play is in town. On the first day, the play sells 4 senior citzen tickets and nine child tickets for a total of $86 dollars. On the next day, the play sells 2 senior citzen tickets and 8 child tickets and makes $64 dollars. So, what is the price of one senior citizen ticket and one child ticket?
Anonymous
Favorite Answer
4s+9c=86
2s+8c=64
and solve for s , c
?
s = cost of a senior citizen ticket
c = cost of a child ticket
On the first day, 4s+9c=86
On the second day, 2s+8c=64
Multiply the second equation by -2 to get
-4s-16c= -128
4s+9c=86
Combine both equations to get
-7c= -42
Divide both sides by -7 to get
c=6
plug that back in as c to get
s=8
ranjankar
4s + 9c = 86
2s + 8c = 64
MULTIPLY EQUATION 2 BY 2
4s + 16c = 128
4s + 9c = 86
SUBTRACT
7c = 42
c = $6
s = $ 8 ANSWER