A cube of 11cm edge is immersed completely in a rectangular vessel containing water.If the dimensions of the base of the vessel are 15cm x 12cm ,find the rise in water level in cms correct to 2 decimal places ,assuming that no water overflows.
I need a solution to this sum please :)
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Favorite Answer
Displaced volume of the water in the vessel is 11 cm x 11 cm x 11 cm and this must be equal to 15 cm x 12 cm x h, where is the raise in water level. Therefore
h = (11 cm x 11 cm x 11 cm) / (15 cm x 12 cm) = 7.39 cm
DWRead
volume of cube = 11³ cm³
area of base of vessel = 15Ã12 = 180 cm²
11³/180 â
7.39 cm
Hosam
change in volume = volume of cube = 11^3 =1331 cm^3
Therefore change in water level = 1331/(15(12)) = 7.39 cm