Differential Equations help, linear high order?

y"-6y'+13=0

Ok so I characterize it to

r^2-6r+13=0

How do I then factor that and how do I then get the answer e^3x(C1cos2x+C2sin2x)

2014-03-09T19:01:34Z

LOL YES! Every time I factor it I get something way different than Wolfram tells me and I dont even know where to begin with plugging said factor into the equation. Even my book factors things different that I do.

2014-03-09T19:04:50Z

so here is what I get when I factor

3+/- 2i

My books answers are always different and how does my factor work into the answer?

david2014-03-09T19:30:42Z

Favorite Answer

E^(3+2i)x = e^3x e^2ix = e^3x (cos2x + I sin2x).
And a similar expression for 3-2i

So your answer is equivalent to the book answer

CogitoErgoCogitoSum2014-03-10T01:56:38Z

Did you just ask 'how do you factor (a quadratic)'?