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wana bigger bike
Lv 6
wana bigger bike asked in Science & MathematicsMathematics · 7 years ago

Differential Equations help, linear high order?

y"-6y'+13=0

Ok so I characterize it to

r^2-6r+13=0

How do I then factor that and how do I then get the answer e^3x(C1cos2x+C2sin2x)

Update:

LOL YES! Every time I factor it I get something way different than Wolfram tells me and I dont even know where to begin with plugging said factor into the equation. Even my book factors things different that I do.

Update 2:

so here is what I get when I factor

3+/- 2i

My books answers are always different and how does my factor work into the answer?

2 Answers

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  • david
    Lv 6
    7 years ago
    Favorite Answer

    E^(3+2i)x = e^3x e^2ix = e^3x (cos2x + I sin2x).

    And a similar expression for 3-2i

    So your answer is equivalent to the book answer

  • CogitoErgoCogitoSum
    Lv 7
    7 years ago

    Did you just ask 'how do you factor (a quadratic)'?

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