a)Find the molecular formula of this compound if the Formula mass is 62.12 g/mole.
b)Determine how many H atoms would be in a 3.50g sample of this compound.
Bobby
Moles of C in the compound = 38.67 / 12 = 3.223 moles
moles of H = 16.22 / 1 = 16.22 moles
moles of N = 45.11 /14 = 3.223
molar ratios in the compound C:H:N = 3.223 :16.22: 3.223
divide by the smallest number 3.223 and we get 1:5:1
empirical formula is CH5N
empirical mass is ( 12+5+14) = 31 g
molar mass is 62.12 g so there are 2 empirical units in a mole of compound
molecular formula is C2H10N2
moles of compound in 3.50 g = 3.50 / 62.12 = 0.056342563 moles
there are 10 moles of H in a mole of the compound so we have 0.56342563 moles of H in the mass
so number of atoms = 6.02 *10 ^23 atoms / mol * 0.56342563 mole
= 3.392 *10^+23 atoms of H in the sample mass