what is the length and width of a rectangle whose area and perimeter is 51cm^2 and 40m?

Michael2015-07-13T05:09:41Z

lw = 51 ===> l = 51/w
2l + 2w = 40

Substitute for l
2(51/w) + 2w = 40

Multiply both sides by w
102 + 2w² = 40w
2w² - 40w + 102 = 0

Divide both sides by 2
w² - 20w + 51 = 0

Factor
(w - 3)(w - 17) = 0

w = {3, 17}

The rectangle is 3 by 17 <-----



m07132015

20

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