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what is the length and width of a rectangle whose area and perimeter is 51cm^2 and 40m?
1 Answer
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- ?Lv 76 years ago
lw = 51 ===> l = 51/w
2l + 2w = 40
Substitute for l
2(51/w) + 2w = 40
Multiply both sides by w
102 + 2w² = 40w
2w² - 40w + 102 = 0
Divide both sides by 2
w² - 20w + 51 = 0
Factor
(w - 3)(w - 17) = 0
w = {3, 17}
The rectangle is 3 by 17 <-----
m07132015
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