Short word problem help?

There were 8 more students in the afternoon class than in the morning class. Together, there were 56 students in both classes. How many students were in each class?

megalomaniac2015-12-03T10:11:57Z

Let A = the number of students in the afternoon
Let M = the number of students in the morning

A = M + 8
A + M = 56

Combine the two equations:

(M + 8) + M = 56

Reduce:

2M + 8 = 56
2M = 48
M = 24

Plug the value of M back into the first equation to get the value of A

A = M + 8
A = 24 + 8
A = 32

DWRead2015-12-03T10:14:23Z

a = m+8
a+m = 56

substitution
(m+8)+m = 56
m = 24
a = m+8 = 32

Anonymous2015-12-03T10:15:04Z

24 students in the morning class and 32 in the afternoon class, I done 56 divided by two is 28 and take away 4 from that to get 24 but add 4 to 28 to get 32 as it gives you the 8 student difference. Hope this helped c:

MICHAEL K2015-12-06T08:29:36Z

56 - 8 = 48 then 48/2 = 24, so the morning class has 24 students and the afternoon class has 32 students.

John H2015-12-03T10:12:53Z

24 in 1st,, 32 in 2nd