take out the factor out of the square root:
1.sqrt of (27c^6) where c

Question

take out the factor out of the square root:
1.sqrt of (27c^6) where c<0 2.sqrt of (72a^4) 3.sqrt of (3y^2) where y<0
HELP PLEASE!!?

Iggy Rocko · Accepted Answer

√(27c^6) =
√(9c^6)√3 =
3|c^3|√3
Since we know c < 0,
3|c^3|√3 = -3c^3√3

√(72a^4) =
√(36a^4)√2 =
6a^2√2
a^2 ≥ 0 for all a so the sign of a doesn't matter

√(3y^2) =
|y|√3
Since y < 0,
|y|√3 = -y√3

take out the factor out of the square root: 1.sqrt of (27c^6) where c<0 2.sqrt of (72a^4) 3.sqrt of (3y^2) where y<0 HELP PLEASE!!?