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take out the factor out of the square root: 1.sqrt of (27c^6) where c<0 2.sqrt of (72a^4) 3.sqrt of (3y^2) where y<0 HELP PLEASE!!?
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- Iggy RockoLv 75 years agoFavorite Answer
√(27c^6) =
√(9c^6)√3 =
3|c^3|√3
Since we know c < 0,
3|c^3|√3 = -3c^3√3
√(72a^4) =
√(36a^4)√2 =
6a^2√2
a^2 ≥ 0 for all a so the sign of a doesn't matter
√(3y^2) =
|y|√3
Since y < 0,
|y|√3 = -y√3
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