4^(x^2-5x+0.25)=sqrt of 2?

Como2016-12-18T20:57:04Z

Favorite Answer

2^[ 2x² -10x + 1/2 ] = 2^(1/2)
2x² -10x + 1/2 = 1/2
[2x] [ x - 5 ] = 0
x = 0 , x = 5

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alex2016-12-18T20:48:34Z

2(x^2-5x+0.25)=(1/2)
2x^2 -10x=0
x=0 or 5

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