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4^(x^2-5x+0.25)=sqrt of 2?

2 Answers

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  • Como
    Lv 7
    4 years ago
    Favorite Answer

    2^[ 2x² -10x + 1/2 ] = 2^(1/2)

    2x² -10x + 1/2 = 1/2

    [2x] [ x - 5 ] = 0

    x = 0 , x = 5

  • alex
    Lv 7
    4 years ago

    2(x^2-5x+0.25)=(1/2)

    2x^2 -10x=0

    x=0 or 5

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