What is the voltage across the resistors, the current passing through, power/heat dissipated, and the power generated by the battery?

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VA=2V given
VR1= 3 -2 =1V
IR1= 1 / 100= .01A
IR2= IR1 = .01A
VR2 = 3 - 1 = 2V
P batt= 3 * .01 = .03W
P R1 = 1 * .01 = .01 W
P R2 = 2 * .01 = .02 W
The circuit is ideal: It is a mathematical model of perfect parts....Show more

In part (i) I think you meant to ask if the battery is ideal (no internal resistance) rather than whether or not the circuit is ideal.

From what is given I don't believe it can be determined whether or not the battery is ideal. If you assume the batteries' emf is 3 Volts then V of R2 is given as 2 Volts but with no resistance value of R2 given, thus no calculable total current from R2's given Voltage. That leaves 1 Volt across (100 Ohms + internal resistance [if any exist] of battery). Again current can not be calculated because the internal resistance is not given nor can it be calculated. Thus the internal resistance value nor it's presence can be determined.

Note; Ideal batteries only exist in homework problems. All real Voltage sources contain a finite internal resistance....Show more

You can use LTSpice to check your work. It's free and works well....Show more

a) 3-2 volts = 1 volt
b) 1 volt/100 ohms = 10 ma
c) same as b)...where else can it go?
d) 2 volts (given)
e) Volts/current = 2 volts/10 ma = 200 ohms
f) Volts*current = 3*(1/100) = 30 mw
g) Volts*current = 1*(1/100) = 10 mw
h) Volts*current = 2*(1/100) = 20 mw
i) What does that mean?...Show more