What is the voltage across the resistors, the current passing through, power/heat dissipated, and the power generated by the battery?

VA=2V given

VR1= 3 -2 =1V

IR1= 1 / 100= .01A

IR2= IR1 = .01A

VR2 = 3 - 1 = 2V

P batt= 3 * .01 = .03W

P R1 = 1 * .01 = .01 W

P R2 = 2 * .01 = .02 W

The circuit is ideal: It is a mathematical model of perfect parts.

In part (i) I think you meant to ask if the battery is ideal (no internal resistance) rather than whether or not the circuit is ideal.

From what is given I don't believe it can be determined whether or not the battery is ideal. If you assume the batteries' emf is 3 Volts then V of R2 is given as 2 Volts but with no resistance value of R2 given, thus no calculable total current from R2's given Voltage. That leaves 1 Volt across (100 Ohms + internal resistance [if any exist] of battery). Again current can not be calculated because the internal resistance is not given nor can it be calculated. Thus the internal resistance value nor it's presence can be determined.

Note; Ideal batteries only exist in homework problems. All real Voltage sources contain a finite internal resistance.

You can use LTSpice to check your work. It's free and works well.

a) 3-2 volts = 1 volt

b) 1 volt/100 ohms = 10 ma

c) same as b)...where else can it go?

d) 2 volts (given)

e) Volts/current = 2 volts/10 ma = 200 ohms

f) Volts*current = 3*(1/100) = 30 mw

g) Volts*current = 1*(1/100) = 10 mw

h) Volts*current = 2*(1/100) = 20 mw

i) What does that mean?