How do you get mean and standard error from just the population mean and standard deviation?
A sample of 50 retirees whose mean is 75 age and standard deviation is 6 years.
A sample of 50 retirees whose mean is 75 age and standard deviation is 6 years.
cidyah
What is given is the sample mean. 50 is the sample size.
Estimate of the population mean = sample mean = 75
standard error = standard deviation / sqrt( sample size) = 6/sqrt(50) = 0.8485
Alan
mean = population mean =75
standard error = population standard deviation / sqrt(N) = 6/sqrt(50) = 6/ sqrt(25)*sqrt(2)
where N = sample size
standard error = (6/5)*( 1/sqrt(2) )= 6*sqrt(2)/ 5*2 = 3*sqrt(2)/5
standard error = 3*sqrt(2) / 5 = approx. 0.848528137
standard error = exactly 3*sqrt(2) /5
standard error = approx. 0.848528137