Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
How do you get mean and standard error from just the population mean and standard deviation?
A sample of 50 retirees whose mean is 75 age and standard deviation is 6 years.
2 Answers
- cidyahLv 74 years ago
What is given is the sample mean. 50 is the sample size.
Estimate of the population mean = sample mean = 75
standard error = standard deviation / sqrt( sample size) = 6/sqrt(50) = 0.8485
- AlanLv 74 years ago
mean = population mean =75
standard error = population standard deviation / sqrt(N) = 6/sqrt(50) = 6/ sqrt(25)*sqrt(2)
where N = sample size
standard error = (6/5)*( 1/sqrt(2) )= 6*sqrt(2)/ 5*2 = 3*sqrt(2)/5
standard error = 3*sqrt(2) / 5 = approx. 0.848528137
standard error = exactly 3*sqrt(2) /5
standard error = approx. 0.848528137
