Use implicit differentiation to find dy/dx and d2y/dx2. x^2 + y^2 = 5, at the point (2, 1)?

x^2 + y^2 = 5
2x + 2y * dy/dx = 0, dy/dx = -2x/2y;  at (2,1), dy/dx = -2/1 = -2.
2 + 2y(d^2y/dx^2) + 2dy/dx = 0,    d^2y/dx^2 = (-2dy/dx - 2)/2y ;
at (2,1), d^2y/dx^2 = (-2*-2 - 2)/(2*1) = 2...Show more