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Use implicit differentiation to find dy/dx and d2y/dx2. x^2 + y^2 = 5, at the point (2, 1)?
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- fcas80Lv 710 months ago
x^2 + y^2 = 5
2x + 2y * dy/dx = 0, dy/dx = -2x/2y; at (2,1), dy/dx = -2/1 = -2.
2 + 2y(d^2y/dx^2) + 2dy/dx = 0, d^2y/dx^2 = (-2dy/dx - 2)/2y ;
at (2,1), d^2y/dx^2 = (-2*-2 - 2)/(2*1) = 2
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