A nice math problem...?

There is no error,

this type of dislogical reasoning is just plain stupid,

Three man gave 10 bucks each, 30 total

bell boy took 5 back 25 total

just for future reference 25 / 3 = 8 and 1/3

So each man did not pay 9 bucks, each man payed $8.33

so if you add 1 dolar that they got back ,, 8.33 + 1 = 9.33

and you add all three of theirs 9.33 + 9.33 + 9.33 = 27.99 or 28

and plus 2 bucks form the bell boy .,.,.. 28+2 = 30

ding ding ding

There is no reason to add the 2 dollars to the 27. That is flawed logic. Each man has paid 9, so 3 x 9 = 27

Of the original 30, the manager has 25, the bellboy has 2 and the men have the other 3

Alright this problem wasnt set up right. Each guy did not pay 9 dollars each. $30 - $2 = $28. So since the bellboy stole $2 then lets just say they came in there with $28. $3 was returned so the room was actually $25. $25 divided by 3 = $8.333333333333333333. So the 3 guys paid that much a peice for the room.

The problem is that the question is always cleverly phrased to conceal what is really going on. Since I don't want to just give you the answer, I'll tell you how I think about it and then you can see if you understand it.

First let's locate all that money. There are two ways to think about how much money is there, and the trick in this question is that it combines the two ways:

1. How much money did the men originally pay?

2. How much money did they end up paying?

For (a), we need to account for $30. The owner keeps $25, the bellboy gets $2, and the men get $3 back. That adds up fine.

Now let's look at (b). How much money did the men end up paying? $27, of which $25 went to the owner and $2 to the bellboy. That adds up too.

The problem with the question is that the $2 the bellboy gets is already contained in the $27 that the men end up paying, so we shouldn't expect adding that $2 to anything to be meaningful.

You don't add the $2 to the amount each man paid, you subtract it. 3 x 9 = $27 - $2 = $25, which is the actual cost of the motel room. The men paid paid the cost of the motel ($25) plus the $2 tip for the bellboy. 25+2= 27. The original $30 that was paid shouldn't be part of the equation.

The cost of the room is $25. Divided by 3 is $8 1/3 each, not $9.

Each man was due $1 2/3 change. The bell boy shorted each of them 2/3 of a dollar, times 3 men is $2 for the bell boy.

there is no error because it all adds up to 30 see 25 for the room and 2 for the bellboy and the 3 that he gave back to the 3 men.

the 3 men did not paid 9 dollars each.

the 3 men actually paid $25, since the $5 was given back.

and since they got $3 back, $1 each

that will make it $25 + $3 = $28.

the remaining $2 is in the bellboy's pocket.

there's no missing $1.

The $2 that the bellboy took should get subtracted, not added to the $27 that the tenants paid total to come up with the $25 going to the hotel.

its like this the room is only 25 which the manager has... the bellboy took two bucks.. which is 25 + 2 = 27

9 * 3 = 27 its fine

If they were overcharged by $5, then they actually paid $35 for the $30 dollar room, and therefore the whole math equation is just meant to trick the reader into thinking they paid $30.