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Write this ratio in the simplest form, x sq. - 1/x sq. - x.?

Trying to study for a final help.

5 Answers

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  • MsMath
    Lv 7
    2 decades ago
    Favorite Answer

    x^2 - 1/x^2 - x

    The common denominator will be x^2

    x^2 = x^2(x^2/x^2) = x^4/x^2

    1/x^2 = 1/x^2

    x = x(x^2/x^2) = x^3/x^2

    x^2 - 1/x^2 - x

    = x^4/x^2 - 1/x^2 - x^3/x^2

    = (x^4 - 1 - x^3)/x^2

    = (x^4 - x^3 - 1)/x^2

    Option 2: Do you mean (x^2 - 1)/(x^2 - x)?

    Factor each one.

    x^2 - 1 is a difference of squares

    x^2 - 1= (x+1)(x-1)

    x^2 - x: You can take out a common factor, x.

    x^2 - x = x(x-1)

    (x^2 - 1)/(x^2 - x)

    = [(x+1)(x-1)]/[x(x-1)]

    The (x-1)'s will cancel

    Answer: (x+1)/x

  • 2 decades ago

    x^4-x^3-1 / x^2

  • 2 decades ago

    x^2 - 1/x^2 - x

    =(x^4-x^3-1)/x^2

  • 2 decades ago

    x2-1/

    x2-x

    I think the x2's cancel out as 1 and a negative divided by a negative= a positive so it would be 1+1x or in proper mathematical form X+1.

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  • 2 decades ago

    1 over -x2

    becuase you simplify x^-1 which ends up being 1 over x

    simplify -x and it is -x over one

    it is intended to be divided so take the reciprocal of -x over one which becomes 1 over -x

    multiply 1 over -x and 1 over - x

    so it ends up being 1 over -x^2

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