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Write this ratio in the simplest form, x sq. - 1/x sq. - x.?
Trying to study for a final help.
5 Answers
- MsMathLv 72 decades agoFavorite Answer
x^2 - 1/x^2 - x
The common denominator will be x^2
x^2 = x^2(x^2/x^2) = x^4/x^2
1/x^2 = 1/x^2
x = x(x^2/x^2) = x^3/x^2
x^2 - 1/x^2 - x
= x^4/x^2 - 1/x^2 - x^3/x^2
= (x^4 - 1 - x^3)/x^2
= (x^4 - x^3 - 1)/x^2
Option 2: Do you mean (x^2 - 1)/(x^2 - x)?
Factor each one.
x^2 - 1 is a difference of squares
x^2 - 1= (x+1)(x-1)
x^2 - x: You can take out a common factor, x.
x^2 - x = x(x-1)
(x^2 - 1)/(x^2 - x)
= [(x+1)(x-1)]/[x(x-1)]
The (x-1)'s will cancel
Answer: (x+1)/x
- stick manLv 62 decades ago
x2-1/
x2-x
I think the x2's cancel out as 1 and a negative divided by a negative= a positive so it would be 1+1x or in proper mathematical form X+1.
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- 2 decades ago
1 over -x2
becuase you simplify x^-1 which ends up being 1 over x
simplify -x and it is -x over one
it is intended to be divided so take the reciprocal of -x over one which becomes 1 over -x
multiply 1 over -x and 1 over - x
so it ends up being 1 over -x^2