the ratio of the corre. sides of 2 similar triangles...?

since the base of one triangle is 9/5 of the other, the height of this triangle is also 9/5 of the other.

area1 = (base)(height)/2

therefore area2 = ((9/5)base)((9/5)height)/2

= (9/5)^2 [(base)(height)/2]

therefore the area of the larger triangle will be (9/5)^2 = 81/25 times that of the smaller triangle

hmm...

Assume that the smaller triangle's area is 5, and that they are isosceles. In this case, the height is 2. So, with a scaling ratio if 5:9, multiply 2 by 9/5 to get your new height of 3.6.

9 * 3.6 / 2 equals 16.2, so that is your new area. Divide 16.2 by 5 to get your area ratio of 3.24:1.

The following is the same for all other triangles. Try it!

ratio is 25:81 because ratio of areas of two similar triangles is equal to ratio of squares of corresponding sides. To get latest question papers on this topic visit http://www.cbsemath.com/

The area of two similar traingle is proportional to the square of corresponding sides .It can be proved .

Hence the answer will be 25: 81.

(5^2) to (9^2)

25 to 81