Please help...A man has 3 sons and 17 horses, he knows he is going to die...?

The Distribution would be :

First son : 9 horses

Second Son : 6 horses

Third Son : 2 horses

Right !!!!!!!!!!!!

Reason being:

Ratio would be 1/2:1/3:1/9

Taking the LCM we get 54 so the ratio now becomes:

27/54:18/54:6/54

Or Simply :

9:6:2

Easy. Isn't it ?

I have seen people trying to answer this question by adding up one extra horse. Which completely destroys the question. The first son should get half of 17 not 18 horses.

Even if i verify the answer

First son got 9 which is not 1/2 of 17 horses.

same gores for other three

mathematically

1st son should get 17(1/2)

2nd son should get 17(1/3)

3rd son should get 17(1/9)

and if i add all this it should be equal to 17.

17(1/2)+17(1/3)+17(1/9)=17

after solving it comes down to this 17=18

Which is a mathematical impossibility i.e. Question is wrong and has monkey business involved.

I lend the man 1 hores so he now has 18 horses. The first son gets 9 (1/2 of 18 is 9). The second son gets 6 (1/3 of 18 is 6). The third son gets 2 horses ( 1/9 of 18 is 2). So the first son gets 9 the second 6 and the third 2. 9+6+2= 17 so I take my one hores back.

17 Horses Riddle

This can be solved easier if you lend a horse to them so it makes 18:

1/2 of 18 = 9

1/3 of 18 = 6

1/9 of 18 = 2

surprisingly the total is 17, so you get the horse you lend them back :)

9-6-2

Oh boy...well the father's wise neighbor came over and added his horse so they had 18

The oldest son got 9

The second oldest got 6

and the third got 2

Then the wise neighbor took his horse back...

.........one of the horses is pregnant and will deliver on the day the dude dies. There won't be any problem by then, would there? The 9-6-2 formula can then be effectively applied...........howz that?

first person shares 8 horses ,

second one shares 6 horses,

third one shares 3 horses

1st son - 9

2nd son - 6

3rd son - 2