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Riddle me this !?
Three men went to a motel. The motel manager said a room cost $30, so each man put up $10 and went to their room. A little while later the manager realized the room was only $25, so he sent the bellhop back to the three guys' room with $5. On the way to the room the bellhop couldn't figure out how to split the $5 between the 3 men, so he gave each one of them $1 and he kept the other $2.
This meant that the 3 men paid $9 each for the room for a total of $27. Add the $2 that the bellhop kept = $29.
Where did the other dollar go?
13 Answers
- Anonymous1 decade agoFavorite Answer
Subtract the $2 that the bellhop kept instead of adding.
They paid $9 each for a total of $27. The hotel received $25 and the bellhop received $2.
- 1 decade ago
The answer is in the way the question is worded. You cannot add what one person HAS to what someone else has PAID and come up with any kind of a meaningful number, you have to subtract.
Each man has paid $9.
The bellhop has $2.
Difference
$9 x 3 = $27
2
$25
The hotel clerk has the other 25 dollars.
To look at it from the standpoint of the original $30. Each man has $1.
The bellhop has $2.
The hotel clerk has $25.
Total
$1 x 3 = $3
2
25
$30
- Anonymous1 decade ago
Each man did not pay $9.00. When the manager refunded the $5, that meant the cost of the room was $25.00, so each man paid $8.33 1/3 for a total cost of $25.00. The other $5.00 was divided between the 3 men ($1 each) and the bellhop kept the remaining $2.00 for a total of $30.
- 1 decade ago
the bellhop was one of the 3 men stayin in the room?
he gave the other men their dollar including himself =$3 plus he kept the other remaining $2 which = $5
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- 1 decade ago
You don't add the $2 the bell hop kept, it is part of the $27. $25 for the room and $2 for the bell hop = $27 = $9 each.
- ☠Naz☠Lv 61 decade ago
its there, 25 for the room 2 for the theiving bellhop and 1 for each of the "HETEROSEXUAL" men. 30 dollars
- Anonymous1 decade ago
umm 25 + 3 =28 dollars not 27,