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Anonymous
Anonymous asked in Education & ReferenceHomework Help · 1 decade ago

The sum of the first n terms of the sequence 1, 2.25, 3.5... can be found by using the formula ...?

S=n/2 [2+(n=1) x 1.25]

use this formula to find the sum of:

a) the first 5 terms.

b)the first 17 terms

im totally stuck on this problem, i dont even know how to start! can anyone give me any suggestions on how i can go about solving it?! all help appreciated!

thanks soo much.

Update:

god, im really sorry, i typed the formula wrong. its meant to be:

S=n/2 [2+(n-1)x1.25]

sorry! :$

3 Answers

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  • raj
    Lv 7
    1 decade ago
    Favorite Answer

    a).S5= (5/2)[2+4(1.25)]=17.5

    S17=(17/2)[2+16(1.25)]=187

  • 1 decade ago

    Shouldn't the equation read S = n/2 [2+(n-1) x 1.25?

    If you want 5, replace n with 5

    If you want 17, replace n with 17

    See if you replace n with 1 then it is 1/2[2+(1-1) x 1.25 = 1

    replace n with 2 then it is 2/2[2+(2-1) x 1.25 = 3.25

    see, that was the sum of the first 2 terms, 1 and 2.25.

    put 5 in there and the equation will be 5/2[2+(5-1)x 1.25 = 17.5

    check my math

  • 1 decade ago

    I think the pattern is 1.25 has been added to each number so the next five numbers would be 4.75, 6, 7.25, 8.5, 9.75, 11 and so on

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