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The difference of the differences of the squares of any two consequtive numbers is ?
The difference of the differences of the squers of any two consequtive numbers is " a static" number always. Numbers considered are the simple whole numbers on the number line generelly used in arithematics. What is it ? Simple but difficult question, should be answered within 24 hours.
14 Answers
- 1 decade agoFavorite Answer
It's always 2....... And alsooo the consecutive differences of squares of two consecutive numbers are always consecutive odd numbers.....
- 1 decade ago
let the first number be defined as x and the second one as y, where x and y are whole numbers and y=x+1.
then, Y^2 - X^2 = (Y - X)(Y + X)
since Y=X+1 => (X + 1 - X)(Y + X)
=> (1)(Y+X)
this is the mathematical proof that the difference of the squares of two whole numbers is equal to the sum of the numbers
as for the other answers you have to be careful and do not make mistakes when working with negative number ( the 2a+1 example )
- ?Lv 44 years ago
enable x be the extra beneficial form and y the smaller. Then: x - y = 3 x^2 - y^2 = 39 y = x - 3 So x^2 - (x - 3)^2 = 39 x^2 - x^2 + 6x - 9 = 39 6x = 40 8 x = 8 to verify: y = 5 8^2 = sixty 4, 5^2 = 25 and sixty 4 - 25 = 39 as required = A
- 1 decade ago
It's "2" the difference of the differences of the squares of two consecutive numbers.
eg: 2^2-1^2=3
3^2-2^2=5
5-3=2
Source(s): Hard thinking - How do you think about the answers? You can sign in to vote the answer.
- Anonymous1 decade ago
The difference of the the squares of any two consecutive numbers is the sum of the two mumbers.
But what you have asked is something else which I don't understand. Maybe you meant the 'difference of the differences' of the squares of three consecutive numbers. In this case, the answer is two.
- Anonymous1 decade ago
This question is in the form of b^2-a^2 where b=a+1.
b^2-a^2=
(a+1)^2-a^2
a^2+2a+1-a^2
2a+1
so that answer is that you take the smaller number double it and add one.
Exmaple Let a=5 and b=6 accourding to the formula the answer should be 2(5)+1=11
b^2-a^2=
6^2-5^2
36-25
11
- grandpaLv 41 decade ago
if n is the smaller number,
the next consecutive number is n+1
so square of (n+1) = nsquare+2n+1
square of n = nsquare
so difference = 2n+1
so the answer for
difference of the differencesof any two consecutive numbers is
2 times the smaller number plus one
- Anonymous1 decade ago
choose two consecutive numbers
a+b and a+b+1
squares are a^2+2ab+b^2 and a^2+b^2+ 2ab +2a +2b +1
difference between squares is 2a+2b+1
now choose two different consecutive numbers
a+c and a+c+1
the difference between the difference of the squares is
|2b-2c| independent of a.
now set b=0 ...
- Anonymous1 decade ago
the difference will be the sum of the two numbers.