Math 24 - need some examples for a school activity?

For those who don't know Math24 (like me)

A standard Math 24 card consists of four digits arranged radially around the center of the card.

(See the 2nd link to see what the cards look like.)

The number (and color) of dots in the corner of a card indicates the difficulty (and point value) of that particular card. Cards are double-sided, with a different set of numbers on each side.

A card is solved by using all four digits on the card exactly once to form a total of 24, using addition, subtraction, multiplication, and/or division. Digits may be used in any order, and any result from a previous mathematical operation can be used in a future operation for that card. For example, a card with the digits 2, 3, 6, and 9 could be solved by stating that 6-3=3, 3+9=12, and 12x2=24. There is often more than one answer to a card. A second solution could be that 9x3=27, 6/2=3, and 27-3=24.

Each digit on the card must be used exactly once in an answer. The solution to the above card could not be 3+9=12, 12x2=24, as the digit 6 is completely unused. Also, the solution could not be 2x6=12, 12-3=9, 9+9=18, 18+6=24, as the number six is used twice.

Cards are divided into three levels of difficulty. One-dot cards (with a single white dot in each corner) are often solved by simple addition, or contain three digits that can make 24, plus a 1 (in which case any other digit could be multiplied or divided by 1 to create the same digit). Two-dot cards (with two red dots) are slightly more difficult, and often require more multiplication and division than one-dot cards. Three-dot cards (with three yellow dots) are the most difficult cards, often having only one solution. In most decks of Math 24 cards, the ratio of one-dot cards to two-dot cards to three-dot cards is 1:2:1.

In all versions, the loop of the digit 9 is filled in with red, so that it is distinguished from the digit 6.

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2 2 2 2: [(2 x 2) + 2 - 2] ! = 24

3 3 3 3: [(3 x 3) x 3] - 3 = 24

4 4 4 4: (4 x 4) + 4 + 4 = 24

5 5 5 5: (5 x 5) - (5/5) = 24

6 6 6 6: (6 x 6) - (6 + 6) = 24

8 8 8 8: [8/ {(8 + 8)/8}] ! = 24

9 9 9 9: (9 + 9) + sqrt 9 + sqrt 9 = 24

(I do not know if the square root sign or the factorial sign are allowed, Teachers may say "too difficult for this age-group")

Somebody asked about 3 3 8 8 recently and I came up with the following answers:

3 3 8 8: [8 / (8 - 3 - 3)] ! = 24

3 3 8 8: [8 / (3 - 8/3)] = 24

and if other base maths than base 10 are allowed: how about:

base 9: 3 + 3 + 8 + 8 = 2 (9s) + 4 units = 24

base 11: 3^3 - 8/8 = 2 (11s) + 4 units = 24

base 12: 3^3 + 8/8 = 2 (12s) + 4 units = 24

But some easy examples with 2 solutions would be:

1 1 4 7: (4 - 1) x (7 + 1) = 24 OR (7 - 1) x (4 x 1 = 24

1 3 4 5: (4 - 1) x (5 + 3) = 24 OR (3 + 1) + (4 x 5) = 24

1 3 4 7: (7 x 3) + (4 - 1) = 24 OR (7 x 4) - (3 + 1) = 24

2 3 5 7: (5 x 3) + (7 + 2) = 24 OR (3 x 7) + (5 - 2) = 24

2 6 8 9: (2 x 8) x (9 / 6) = 24 OR (2 x 9) x (8 / 6) = 24 or if factorials are allowed: 6 + 2 x (9! / 8!) = 24

Is that the game where you get 4 numbers and try to make 24 out of them?

the numbers:

1, 2, 3, 4

4 x 3 = 12, 12 x 2 = 24, 24 ÷ 1 = 24

the numbers:

5, 6, 2, 3

6 x 5 = 30, 2 x 3 = 6, 30 - 6 = 24

Math 24 Solutions

If it were that simple, more people would do it. The thing is, not all classes are 3 hours. Some are 4, and often you cannot get everything you want each semester. Some courses are fall only, or spring only. Trust me, there are many kinks that get thrown into the best laid plans of college students. Summer classes are usualy where you have to make that up. Sure, you may want to take 6 3-hour classes per week...but it's hard, and not every course you need will be available (or it might overlap with another class or two). In theory, your idea is good. It just rarely works out that way.

THERES A GRADE 24!?!?!??! ah crap...