Got some math problems I don't understand, Help Please?

1 factor the x... x(x+2) = 0 set both = 0, so x=0, x=-2

2. factor the x ... x(x^2-4) = 0 then (difference between squares)

x(x+2)(x-2)...set all to 0 and solve so.. x=0, x=-2, x=2

3. factor......(x-3)(x+5) so x = 3 x=-5

4. factor the x.... x(x^2+8x+16) = x(x+4)^2 so x =0 x=-4

5. factor.... (x^2-4)(x^2-9)....then difference between squares ....

(x-2)(x+2)(x-3)(x+3)......x = -3, x = -2, x=2, x=3

For the first one you can factor an x out of each and you get:

X(X+2)=0

Set the X outside the parentheses to 0 and x+2 equal to 0

X=0

X=-2

For #2 Again you can factor out an X.

x(x^2-4)

Then you can factor the X^2-4 into:

(x-2)(x+2) then all of that times the x you factored out

x(x-2)(x+2)

set each to zero

x=0 (x-2)=0 (x+2)=0

The answers are 0, 2, & -2

For #3, Factor like normal (x+5)(x-3) To check this do 5*-3= -15 and -3+5=2 (the middle term)

Set each to zero and solve

#4 Factor out an X and factor as usual

Not sure out to do #5

Good luck and hope i helped!

You did them in the correct manner. Here are the answers to check with yours.

1. -2

2. 0, 2, -2

3. 3, -5

4. 0, -4

5. 2, 3

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