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Question on differentiation?
The radius of a circular soap bubble is increasing at a rate of 0.2cm/s. Find the rate of increase of its surface area, when the radius is 7cm.
surface area = 4pi r^2
2 Answers
- MawkishLv 41 decade agoFavorite Answer
This is going to be tricky to demonstrate on here without mathematical symbols, but I'll try my best:
For this description I will use the following notation:
* means 'multiplied by'
/ means 'divided by'
^ means 'to the power of'
pi means 3.1415926535...
A = 4pi r^2
where A is the surface area of the bubble and r is the bubble's radius. This could be re-written:
dA = 4pi dr^2
Now, we know that:
dr/dt = 0.2
We can approximate
dr^2/dt = 0.2r
From the equation above (multiplying both sides by dr). Now rearrange the second equation to get:
(1/4pi) * dA = dr^2
and divide through by dt:
(1/4pi) * (dA/dt) = dr^2/dt
We already know dr^2/dt from the fourth equation above, so we can rewrite this as:
(1/4pi) * (dA/dt) = 0.2r
And rearranging this gives:
dA/dt = 0.2 * 4pi * r
We want to find dA/dt at the radius 7cm, so this is:
dA/dt = 0.2 * 4pi * 7 = 17.6 cm^2/s
And that's the answer, 17.6cm^2/s
PS: I think I have this right but I've been off for Christmas and my brain has turned itself off. The units all balance and I can't see any obvious mistakes but if anyone sees any, please say!!!
PPS: Ojo's differentiation is with respect to the radius, not with respect to time (as is required)
- 1 decade ago
Differentiation can be interpreted as the rate of change of area.
We need to get the differential of 4pir^2
the differential of 4pi r^2 is 8pi r dr
8 pi (7cm)(0.2cm/s)= the answer is 11.2cm^2/s