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indefinite intergral of tan 4x dx?

Hi,

A simple question on how to solve the indedinite intergral of:

S tan(4x) dx. The S is my integral sign.

2 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    Well for tanx the integral is ln(secx) + C, so for tan4x it will be:

    ln(sec(4x)) / 4 + C

    Because if you derive ln(sec(4x)) you'll get 4*tan(4x).

  • 1 decade ago

    = S (sin 4x / cos 4x)dx

    put cos 4x= t ; -4sin 4x dx = dt

    =log (sec 4x)/4

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