What's wrong with this (math students?)?

There is a divide by 0 error. (a+b+c)=0 so you can not divide that.

i think where you went wrong is the second line

see it should be (4a-3a)+(4b-3b) = (4c-3c)

it is a mathematical problem splitting up the a's b's and c's

yeah, what ace said.

suppose a=2, b=3, c=5. the last step of the solution, requires that both sides be divided by (a+b-c). substituting, we find (2+3-5) = 0. since dividing by zero is undefined, this last step is invalid.

If a+b=c, then a+b-c is the same as c-c, which, no matter what c is, equals 0, so you can't factor a+b-c out of the equation.

Haha, interesting...

thanx for that, i've stared your question.....

i dont know wat the f**ck yall talkin' bout cuz im in the 6th grade soooooooooooo....................

i bet it is funny

(if i understood)