Masters of Vectors are welcomed!?

First, Determine his position.

If we say he started at 0,0

and the camp is at 0,5.4

during the white out he traveled to

7.8*cos(53),7.8*sin(53)

4.69, 6.23

If we now translate the camp to 0,0

his position is

4.69, (6.23-5.4)

or

4.69, .83

the distance is

sqrt(4.69^2+.83^2)

=4.76 km

and the angle is

arctan(.83/4.69) south of west

so he must travel 4.76km 10 degrees south of west to get to camp

j

j

From a point draw a line 5.4 km straight up, and another 7.8 km long at an angle of 53 degrees up from horizontal, which is to say 90-53=37 degrees to the right of the first line, and a third line from the tips of the other two lines. Then use trigonometry to solve the triangle for the length of the third line and the values of the other two angles in the triangle. All vector problems are basically triangle problems.

x=7.8 * cos53