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Can anyone write out the reactants and predict the product??
I need for someone to write out these reactants and predict the products. Here they are, please write the number of the one that you solved next to it:
1) hydrogen peroxide (catalyzed by manganese dioxide)
2) zinc + hydrochloric acid
3) sulfuric acid + sodium hydroxide
4) sodium + hydrogen
5) acetic acid + copper
What I mean by writing out the reactants and predicting the products is, say I have silver nitrate + zinc chloride. Then the reactant would be AgNO3. I have to predict the product, which would be AgCl + Zn(NO3)2. so, the whole thing would be AgNO3---> AgCl+ Zn(NO3)2. Thanks so much to anyone who can solve these. I know pretty much how to do them, but some of them are really hard to figure out. Again, thanks!
3 Answers
- science teacherLv 71 decade agoFavorite Answer
1. 2H2O2---->2H2O +O2(g) (MnO2-catalyst)usually written over the arrow
2. Zn+2HCl--->H2(g)+ZnCl2
3. H2SO4+2NaOH--->Na2SO4+H2O
4. 2Na+H2--->2NaH sodium hydride
5. 2CH3COOH+Cu--->Cu(CH3COO)2 + H2
copper acetate forms if the acetic acid is strong enough
Source(s): 2AgNO3+ZnCl2--->2AgCl(s)+Zn(NO3)2 balanced - steve_geo1Lv 71 decade ago
2H2O2 ===> 2H2O + O2
Zn + 2HCl ===> ZnCl2 + H2
H2SO4 + 2NaOH ===> Na2SO4 + 2H2O
2Na + H2 ===> 2NaH (sodium hydride)
HC2H3O2 + Cu ===> No reaction. Copper is above hydrogen in the electromotive series.
- Anonymous4 years ago
MgBr2 + Cl2 --> MgCl2 + Br2 single displacement. the numbers would desire to be subscript. 2Al + Fe2O3 --> Al2O3 + Fe single displacement. you seem on the charges on the various factors. for magnesium bromide you have mg with +2 and br with -a million charge so that they flow and you place the two with bromide and the only with magnesium and write them as subscript. whilst magnesium bromide react with chloride, the unfavorable chloride displaces the unfavorable bromide ion ensuing in MgCl2 and Br2. i don't be conscious of if that makes total experience... considering's annoying to describe without being able to make references to the periodic table and such.