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i'm in class 10 cbse there was this ques. where the ratio of roots of quadratic equation was given and....
a variable was given in the equation, had to find the value of the variable...
it was something like x^2+(m+2)x+m+2=0 ; there roots are in ratio 2:3 find the value of m
(i cannot remember the exact question)
can someone quote it and tell me how to go about it
plz somebody answer
1 Answer
- Phineas BoggLv 61 decade agoFavorite Answer
Let the roots be 2a and 3a (then they are in the ratio of 2:3. So the equation is (x - 2a)(x - 3a) = 0, which multiplied out is:
x^2 - 5ax + 6a^2 = 0
So you have:
-5a = m+2 and
6a^2 = m+2
so -5a = 6a^2 so a=-5/6.
So the roots are: -5/3 and -5/2.
